(b) How many moles of HCl are present in 35.0 mL of a 4.50 M solution of nitric acid?
mools = M x L
To determine the number of moles of HCl present in the given solution, we need to use the molarity (M) and volume (in liters) of the solution.
Given:
Molarity (M) of nitric acid solution = 4.50 M
Volume of the solution = 35.0 mL
First, we need to convert the volume from milliliters (mL) to liters (L):
35.0 mL = 35.0 / 1000 = 0.0350 L
Next, we can use the formula:
moles = molarity × volume
Substituting the given values:
moles of HCl = 4.50 M × 0.0350 L
Calculating:
moles of HCl = 0.1575 moles
Therefore, there are 0.1575 moles of HCl present in 35.0 mL of a 4.50 M solution of nitric acid.
To find the number of moles of HCl present in the given solution, we need to use the relationship between the concentration, volume, and number of moles.
The formula to calculate the number of moles is:
moles = concentration (in M) * volume (in L)
First, let's convert the volume from milliliters (mL) to liters (L) by dividing by 1000:
35.0 mL ÷ 1000 = 0.035 L (rounded to 3 decimal places)
Now, we can use the formula to find the moles:
moles = 4.50 M * 0.035 L
Calculating this value:
moles = 0.1575 (rounded to 4 decimal places)
Therefore, there are approximately 0.1575 moles of HCl present in 35.0 mL of a 4.50 M solution of nitric acid.