How many fencing materials will be needed if the measurements of the sides of the lot to be fenced are 37.5m and 24.8m?
920 square meters
Fencing means putting up a fence around the perimeter.
For a lot of 37.5 by 24.8, the perimeter would be 2(L+W)=2(37.5+24.8) linear metres.
The height of the fence is not mentioned, so the answer should be in metres in length.
To determine the number of fencing materials needed, we first need to calculate the perimeter of the lot. The perimeter of a rectangle is found by adding up all the sides.
Given the measurements of the sides: 37.5m and 24.8m
The perimeter (P) can be calculated using the formula: P = 2(length + width)
P = 2(37.5m + 24.8m)
P = 2(62.3m)
P = 124.6m
So, the perimeter of the lot that needs to be fenced is 124.6m.
To determine the number of fencing materials needed, we need to know the length of one fencing material. Once we have this information, we can divide the perimeter of the lot by the length of each fencing material.
Let's say each fencing material has a length of 2 meters.
Number of fencing materials needed = Perimeter of the lot / Length of each fencing material
Number of fencing materials needed = 124.6m / 2m
Number of fencing materials needed = 62.3
Therefore, if each fencing material has a length of 2 meters, you would need 62.3 fencing materials to fence a lot with sides measuring 37.5m and 24.8m.