A car traveling at 20 m/s accelerates at 7 m/s2 for 3 sec. How fast is it now traveling? Please help!
Vf=Vi+at
Vf=20 m/s+ 7m/s^2*3s
Vf=41 m/s
To find the final velocity of the car after accelerating for 3 seconds, we can use the equation:
vf = vi + at
where vf is the final velocity, vi is the initial velocity, a is the acceleration, and t is the time.
Given:
Initial velocity (vi) = 20 m/s
Acceleration (a) = 7 m/s^2
Time (t) = 3 seconds
Plugging in the values, we have:
vf = 20 m/s + (7 m/s^2)(3 s)
vf = 20 m/s + 21 m/s
vf = 41 m/s
So, the car is now traveling at a speed of 41 m/s.
To determine the car's final velocity, we can use the formula for acceleration:
final velocity = initial velocity + (acceleration x time)
Given that the initial velocity (u) is 20 m/s, the acceleration (a) is 7 m/s², and the time (t) is 3 seconds, we can substitute these values into the formula:
final velocity = 20 m/s + (7 m/s² x 3 s)
Multiplying the acceleration (7 m/s²) by the time (3 s) gives us the change in velocity, which is 21 m/s.
final velocity = 20 m/s + 21 m/s
Adding the initial velocity (20 m/s) and the change in velocity (21 m/s) gives us the final velocity:
final velocity = 41 m/s
Therefore, the car is now traveling at a speed of 41 m/s.