1)What method(s) would you choose to solve the equation:
x2 + 2x - 6 = 0
A. Square roots; there is no x-term.
B. Quadratic formula, graphing; the equation cannot be factored easily since the numbers are large.
C. Factoring; the equation is easily factored.
D. Quadratic formula, completing the square or graphing; the coefficient of x2-term is 1, but the equation cannot be factored. <<<------
2)What are the solutions of the equation?
c^2 - 10c = 0
A. 1, – squareroot10 <<<----
B. 0, –10
C. 0, sqrt10
D. 0, 10
3)Use the discriminant to determine the number of real-number solutions for the equation:
8x2 + 8x + 2 = 0
A. one solution <<<---
B. two solutions
C. no solutions
D. infinitely many solutions
4)What are the solutions of the equation: z2 - 12z + 36 = 0?
A. -6, 6 <<----
B. 6, 6
C. 6, -6
D. -6, -6
am i right? if not, please help me out. :D
thank u!
Let's go through each question and check if your answers are correct:
1) The correct answer is D. Quadratic formula, completing the square or graphing; the coefficient of x2-term is 1, but the equation cannot be factored. In this case, the equation cannot be easily factored, so we need to use another method like the quadratic formula or completing the square to find the solutions.
2) The correct answer is D. 0, 10. The equation can be factored as c(c - 10) = 0. So the solutions are c = 0 and c = 10.
3) The correct answer is A. one solution. The equation has a discriminant of b^2 - 4ac = 8^2 - 4(8)(2) = 64 - 64 = 0. Since the discriminant is zero, this means there is only one real-number solution.
4) The correct answer is A. -6, 6. The equation can be factored as (z - 6)(z - 6) = 0. So the solution is z = 6. Since both factors are the same, there is only one solution which is z = 6.
So, you got 3 out of 4 correct. Great job!
1. I would choose B.
2. c^2 - 10c = c(c-10) = 0
Now what do you think?
4. z^2 - 12z + 36 = (z-6)(z-6) = 0
Now what do you think?
3. Since it seems like you are just guessing, I did not bother to answer.