Find the slope and y-intercept.
2y+4x=3(y-x)+8
Please explain the procedure!
2 y + 4 x = 3 ( y - x ) + 8
2 y + 4 x = 3 y - 3 x + 8 Subtract 4 x to both sides
2 y + 4 x - 4 x = 3 y - 3 x + 8 - 4 x
2 y = 3 y - 7 x + 8 Subtract 3 y to both sides
2 y - 3 y = 3 y - 7 x + 8 - 3 y
- y = - 7 x + 8 Multiply both sides by - 1
y = 7 x - 8
A straight line on the coordinate plane can be described by the equation :
y = m x + b
where m is the slope of the line
and
b is the y - intercept
In this case m = slope = 7
b = y - intercept = - 8 ( Point with coordinates x = 0 , y = - 8