Chemistry!

So a metal is found to absorb 1000 calories as it is heated from 40.0C to 60.0C. How much heat would the same sample absorb if it were heated from 60.0C to 80.0C?

I know I'm supposed to use the equation Q=s x m x delta t (or soemthing)
Q= energy absorbed
s= specific heat (on metal)
m= mass in grams
delta t = change in temperature

and I'll need to convert calories to joules.

so I'd get 4184 = s x m x 20
but the second equation has the same metal and same delta T, so how much heat would the sample absorb?

the delta temp is the same, mass is same, specific heat is same. Ans: 1000 calories. You don't need to do any math here.

Alright, I had thought that but it seemed a little weird :x thank you!

i belieeve you are working on penn foster :P if you are, you should email me and we can work together on it, im actually almost done with it. my email is rvargas @ live (dot) com. sorry, had to put it that way, cant post email addresses aparently :0

To find out how much heat the sample would absorb when heated from 60.0°C to 80.0°C, we can use the same equation you mentioned:

Q = s x m x delta t

where:
Q is the energy absorbed (heat)
s is the specific heat of the metal
m is the mass of the sample
delta t is the change in temperature

We know that Q = 1000 calories when the sample is heated from 40.0°C to 60.0°C. However, we need to convert calories to joules because the equation requires SI units:

1 calorie = 4.184 joules

So, by converting the Q value, we have:
Q = 1000 calories x 4.184 J/calorie
Q = 4184 joules

Now, we can rearrange and solve the equation to find the specific heat (s):

s x m x delta t = Q

Substituting the known values:
s x m x 20 = 4184

Since the metal and the delta t (change in temperature) are the same in both cases, we can set up a proportion to find the heat absorbed when the sample is heated from 60.0°C to 80.0°C:

1000 calories/20 = x calories/20

Simplifying the proportion:
1000 calories = x calories

Therefore, the heat absorbed by the same sample when heated from 60.0°C to 80.0°C would be 1000 calories, which is equivalent to 4184 joules.