find the force if f between charges of +100mc -50mc located 50cm a part?
Use Coulomb's Law. If you don't know it, Google and review it.
To find the force (F) between charges, we can use Coulomb's Law, which states that the force between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. The equation is given by:
F = (k * q1 * q2) / r^2
where:
F = force between charges
k = Coulomb's constant (k = 9 x 10^9 Nm^2/C^2)
q1, q2 = magnitudes of the charges
r = distance between the charges
In this case, we have q1 = +100 mc (microcoulombs) and q2 = -50 mc. The distance between them, r, is 50 cm.
First, convert the charges to coulombs, as 1 microcoulomb (mc) = 1 x 10^-6 C.
So, q1 = +100 mc = +100 x 10^-6 C = +0.0001 C
And, q2 = -50 mc = -50 x 10^-6 C = -0.00005 C
Now, substitute the values into the formula:
F = (k * q1 * q2) / r^2
= (9 x 10^9 Nm^2/C^2) * (+0.0001 C) * (-0.00005 C) / (0.5 m)^2
= (-0.045 N)
Therefore, the force (F) between the +100 mc and -50 mc charges, located 50 cm apart, is -0.045 N (newtons). The negative sign indicates that the force is attractive, as opposite charges attract each other.