If m< JKN = 8x + 2 and m< MKL = 3x + 5, what is m< MKN? I know the answer but can you give an explanation

more information is needed

What are J, K, N, and M ?
And I even see an L !

!@#$%^&a idk

To find the measure of angle MKN, we can use the fact that the sum of the measures of the angles in a triangle is always 180 degrees.

In this case, we are given that m< JKN = 8x + 2 and m< MKL = 3x + 5.

We know that angle JKN and angle MKL are adjacent angles, which means they share a common side (KN) and vertex (K). Therefore, the sum of their measures should be equal to angle MKN.

So to find m< MKN, we add the measures of angle JKN and angle MKL:

m< MKN = m< JKN + m< MKL
= (8x + 2) + (3x + 5)
= 8x + 2 + 3x + 5
= (8x + 3x) + (2 + 5)
= 11x + 7

Thus, the measure of angle MKN is 11x + 7.

If m<JKN = 8x+2, and m<MKL = 3x+5 , What is m<MKN? I know the answer but can you explain it