In one cycle, an engine burning a mixture of air and methanol (methyl alcohol) absorbs 525 J and expels 413 J.

How much work is done by this engine?

To calculate the work done by the engine, we need to use the First Law of Thermodynamics, which states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system.

In this case, the engine absorbs 525 J of heat (Qin) and expels 413 J of heat (Qout). The change in internal energy (ΔU) can be calculated as follows:

ΔU = Qin - Qout
= 525 J - 413 J
= 112 J

Since the engine is doing work (W), it means that the change in internal energy is equal to the work done:

ΔU = W

Therefore, the work done by the engine is 112 J.

525 - 413