When a driver brakes an automobile, friction between the brake disks and the brake pads converts part of the car's translational kinetic energy to internal energy. If a 1500 kg automobile traveling at 42 m/s comes to a halt after its brakes are applied, how much can the temperature rise in each of the four 3.5 kg steel brake disks? Assume the disks are made of iron (cp = 448 J/kg·°C) and that all of the kinetic energy is distributed in equal parts to the internal energy of the brakes.

To determine the temperature rise in each of the four steel brake disks, we need to calculate the amount of kinetic energy that is converted into internal energy, and then use the specific heat capacity of iron to find the corresponding temperature change.

1. Calculate the initial kinetic energy (KE) of the automobile:
KE = 0.5 * mass * velocity^2
=> KE = 0.5 * 1500 kg * (42 m/s)^2

2. Calculate the total kinetic energy converted to internal energy, as it is distributed equally among the four brake disks:
Total internal energy = KE / 4

3. Determine the change in internal energy using the specific heat capacity:
Change in internal energy = mass_disks * specific heat capacity * temperature_change

- We know the mass of each brake disk is 3.5 kg, and the specific heat capacity of iron is given as 448 J/kg·°C.
- We need to find the temperature change (temperature_change).

4. Rearrange the equation to solve for temperature_change:
temperature_change = change in internal energy / (mass_disks * specific heat capacity)

5. Plug in the values:
temperature_change = (Total internal energy) / (4 * 3.5 kg * 448 J/kg·°C)

6. Calculate the result.

By following these steps, you can find the temperature rise in each of the four steel brake disks.