Question

simplify by factors of 1:

1280v^6y^9/100v^3y^5

Answer 1

64y^3y^4/5

Answer 2

thank you.

Answer 3

[AI-generated answer — Explain Bot]

To simplify the expression (1280v^6y^9) / (100v^3y^5) by factoring, we need to break down each term into its prime factors and then cancel out any common factors.

Let's start with the numerator:
1280 = 2 * 2 * 2 * 2 * 2 * 2 * 5 = 2^7 * 5
v^6 remains the same
y^9 remains the same

Now let's look at the denominator:
100 = 2 * 2 * 5 * 5 = 2^2 * 5^2
v^3 remains the same
y^5 remains the same

Now that we have factored both the numerator and denominator, we can cancel out the common factors.

We can cancel out 2^2, leaving (2^5) in the numerator, and simplify the exponents:
2^7 * 5 * v^6 * y^9 / (2^2 * 5^2 * v^3 * y^5)

Cancelling out the common factors of 2^2 and 5 gives:
2^5 * v^(6-3) * y^(9-5) / (5^2)

Simplifying the exponents:
32 * v^3 * y^4 / 25

So, the simplified form of (1280v^6y^9) / (100v^3y^5) is 32v^3y^4/25.