The force of gravity pulling on an object down a hill is its weight multiplied by the sine of the angle of elevation of the hill.
With how many pounds of force is gravity pulling on a 3000 lb car on a hill will a 3 degree angle of elevation?
What i did:
SIN3=.0523
.0523*3000 = 157 lbs (rounded)
is this correct?
Yes, that is correct
who mans is this?
an observer located 3 km from a rocket launch site sees a rocket at an angle of elevation of 48 how high is the rocket at that moment
Yes, your calculation is correct. To determine the force of gravity pulling on an object down a hill, you can use the formula: force of gravity = weight of the object * sine(angle of elevation).
In your case, the weight of the car is given as 3000 pounds and the angle of elevation is 3 degrees. To find the sine of 3 degrees, you can use a calculator or a trigonometric table. The sine of 3 degrees is approximately 0.0523.
Now, you can plug in the values into the formula:
Force of gravity = 3000 lbs * 0.0523 ≈ 157 lbs
So, the force of gravity pulling on a 3000 lb car on a hill with a 3 degree angle of elevation is approximately 157 pounds. Well done!