What is the kd of ethanoic acid between isobitanol and water?
Do you mean isobutanol? I found this but it isn't free. Perhaps the summary will give the value. I'll continue to look.
http://www.markedbyteachers.com/as-and-a-level/classics/determination-of-the-partition-coefficient-of-ethanoic-acid-between-water-and-butan-1-ol.html
I believe that article lists it as 0.8040 for the partition coefficient.
To determine the Ka of ethanoic acid, we need to know the concentration of its products of dissociation: acetate ions (CH3COO-) and hydrogen ions (H+). The Ka is the equilibrium constant for the dissociation of an acid.
The balanced chemical equation for the dissociation of ethanoic acid (CH3COOH) is:
CH3COOH ⇌ CH3COO- + H+
The Ka expression for this equilibrium can be written as:
Ka = [CH3COO-][H+] / [CH3COOH]
To find the Ka of ethanoic acid, we would need to conduct an experiment to measure the concentrations of CH3COO-, H+, and CH3COOH at equilibrium. However, you mentioned the term "kd," which might refer to the equilibrium constant of a different process.
If you have additional information or clarify what you mean by "kd," I can provide you with a more accurate answer.