A combination lock has 10 dials. To
open the lock, you must turn the dial right to the first number, left to
the second number. What is the probability that you choose the correct combination?
1/10
Someone can correct me if I'm wrong, but you have 10 dials, 1/10 chances.
assuming the same number can be used on the 2nd turn
the number of turns = 10*10 = 100
One of these will be correct
prob of correct choice = 1/100
To find the probability of choosing the correct combination on a combination lock with 10 dials, we need to determine the number of possible combinations and the number of correct combinations.
In this case, each dial can be set to any number from 0 to 9, and we have 10 dials in total. Therefore, the total number of possible combinations is 10^10 (10 options for each of the 10 dials).
To open the lock, we must turn the dial right to the first number and left to the second number. Since we have only one correct combination, the number of correct combinations is 1.
So, the probability of choosing the correct combination is:
Probability = (Number of correct combinations) / (Total number of possible combinations)
Probability = 1 / (10^10)
Probability = 1 / 10,000,000,000
Therefore, the probability of choosing the correct combination on this combination lock is 1 in 10 billion.