Find the value of a in the determinant of {6 3]
[4 a] is
a)6 b)3 c) 0 d)-12
(have the answers just need to know the working to get it)
If there is an "a" in your matrix (which does not look like a matrix, by the way), then there must be an "a" in the determinant.
Is the "a" supposed to be a number?
Are the last two numbers supposed to be lined up below the first two numbers?
find the value of a if the determinant of:(6 3)
(4 a)is:
a) 6 b) 3 c)0 d)12
And yes "a" is suppose to represent a number
I misread this as a multiple choice question. It is actually a multiple (four-part) question.
For each of your four choices of the determinant value, there is a value of a that will work. The determinant value for the matrix
|6_3|
|4_a| is
6a - 12.
a) If the determinant D is 6, then
6a - 12 = 6, and a = 3
b) if the determinant D is 3, then
6a - 12 = 3, and a = 2.5
You do the other two cases.
To find the value of a in the given determinant, we need to evaluate the determinant and set it equal to zero.
The determinant of a 2x2 matrix is calculated as follows:
Det([a b]
[c d]) = (a*d) - (b*c)
Given this information, let's evaluate the determinant of the given matrix:
Det([6 3]
[4 a]) = (6*a) - (3*4)
Now, set the determinant equal to zero:
6*a - 3*4 = 0
Simplify the equation:
6*a - 12 = 0
Add 12 to both sides:
6*a = 12
Divide both sides by 6:
a = 12/6
Simplify:
a = 2
Therefore, the value of a in the given determinant is 2. So the answer is not in the provided options.