math

solve the equation

log2(x+4)-log4x=2

the 2 and 4 are lower than the g

This is what I got:
log2(x+4)+log2(4^x)=2
log2((x+4)*4^x)=2
4^x(x+4)=4
x=0 is a solution???

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  1. log2(x+4) + log4(x) = 2
    log2(x+4) + log2(x)/log2(4) = 2
    log2(x+4) + log2(x)/2 = 2
    2 log2(x+4) + log2(x) = 4
    log2((x+4)^2) + log2(x) = 4
    log2(x(x+4)^2) = 4
    x (x+4)^2 = 2^4
    x^3 + 8x^2 + 16x − 16 = 0

    x = 0.718608

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