balance:
Al2(CO3)3 --> Al2O3 + CO2
i don't know how to do the reactant side so i can figure out the product side...
To balance the reaction:
1. Start by determining the number of atoms of each element on both sides of the equation.
On the reactant side:
- Al: 2 atoms (Al2)
- C: 3 atoms (CO3)
- O: 9 atoms (3 x CO3)
On the product side:
- Al: 2 atoms (Al2O3)
- C: 1 atom (CO2)
- O: 3 atoms (3 x O)
2. Begin balancing with the elements that occur in the fewest number of compounds; in this case, the element Al (aluminum).
To balance the Al atoms, multiply Al2O3 by 2.
The reaction now looks like this:
2 Al2(CO3)3 --> 2 Al2O3 + CO2
3. Next, focus on balancing the C atoms. Since there are 3 CO3 groups on the reactant side, you'll need to multiply CO2 by 3 to balance the carbon atoms.
The balanced equation now becomes:
2 Al2(CO3)3 --> 2 Al2O3 + 3 CO2
4. Finally, check the number of oxygen atoms. On the reactant side, there are 9 oxygen atoms (3 x CO3). On the product side, there are 6 oxygen atoms (3 x O in Al2O3 plus 3 x O in CO2).
To balance the oxygen atoms, multiply Al2O3 by 3.
The final balanced equation is:
2 Al2(CO3)3 --> 6 Al2O3 + 3 CO2
To balance the equation Al2(CO3)3 --> Al2O3 + CO2, you need to ensure that there is an equal number of each type of atom on both sides of the equation. Here's a step-by-step guide to balancing the reactant side:
1. Start by counting the number of each type of atom on each side of the equation.
On the reactant side:
- Al: 2 atoms
- C: 6 atoms (3 multiplied by the coefficient 2)
- O: 18 atoms (3 multiplied by the coefficient 2 and the subscript 3)
2. Identify the atom that appears in the greatest number on either side of the equation. In this case, it is oxygen (O).
3. Manipulate the coefficients to balance the number of oxygen atoms.
- To balance the oxygen atoms on the reactant side, you will need to have 9 molecules of CO3 (3 multiplied by 3) to provide 27 oxygen atoms (9 multiplied by 3).
- Adjusting the coefficient for Al2(CO3)3 to 9, the reactant side becomes:
9 Al2(CO3)3
4. Recount the number of each type of atom on the reactant side:
- Al: 18 atoms (2 multiplied by the coefficient 9)
- C: 54 atoms (6 multiplied by the coefficient 9)
- O: 162 atoms (18 multiplied by the coefficient 9)
Now that the reactant side is balanced, you can move on to balancing the product side.
5. Count the number of each type of atom on the product side:
- Al: 4 atoms (2 multiplied by the coefficient 2)
- C: 1 atom
- O: 3 atoms
6. Adjust the coefficients of the products to balance the equation based on the number of atoms that were balanced on the reactant side:
- To balance the Al atoms on the product side, adjust the coefficient of Al2O3 to 2. The product side becomes:
Al2O3 + CO2
7. Recount the number of each type of atom on the product side:
- Al: 4 atoms
- C: 1 atom
- O: 3 atoms
Now, the equation is balanced with 9 Al2(CO3)3 on the reactant side and 2 Al2O3 + CO2 on the product side.
Ans is - Al2(CO3)3 - Al2O3+ CO2
first, note that there are 2 Al on each side. So, we need to balance the
CO3 and the O3CO2
as written, we have
3C and 9O on the left, and
1C and 5O on the right.
But, 3O are bound to the balanced Al, leaving
1C and 3O to play with. Looks like we just need to triple the CO2:
Al2(CO3)3 --> Al2O3 + 3CO2
Left: 3C,9O
Right: 3C,9O