The price of a jacket at store A is $48. If the price at store B is 5.5% higher, what is the price difference? What is the cost of the jacket at store B?
48 * 1.055 = $50.64
50.64 = 48 = ?
um work please?
Sorry. The last part should be
50.64 - 48 = $2.64
ok well thanks wud bout dis one?
Use the table below. Round to the nearest tenth of a percent.
3. What percent of students are in Pre-K through 8th grade?
71.2%
4. What percent of students are in grades 9–12?
28.8%
Population
(in thousands)
Grades
Pre-K through grade 8
33,952
Grades 9–12
13,736
Total
47,688
You expect people to take you seriously when you post this? "wud bout dis one"
??
Good for Writeacher!
To find the price difference and the cost of the jacket at store B, you'll need to follow these steps:
1. Calculate the price difference:
Price difference = Price at store B - Price at store A
2. Calculate the cost of the jacket at store B:
Price at store B = Price at store A + (Price at store A * 5.5%)
Let's plug in the values:
1. Calculate the price difference:
Price difference = Price at store B - Price at store A
Price difference = Price at store A + (Price at store A * 5.5%) - Price at store A
Price difference = Price at store A * 5.5%
2. Calculate the cost of the jacket at store B:
Price at store B = Price at store A + (Price at store A * 5.5%)
Price at store B = $48 + ($48 * 5.5%)
Price at store B = $48 + ($48 * 0.055)
Price at store B = $48 + $2.64
Price at store B = $50.64
So, the price difference between store A and store B is $2.64, and the cost of the jacket at store B is $50.64.