I've done every other single question besides this one. (There was 12). I'm stumped and would really appreciate some help!

I have to simplify this:
5/3sqrt(3-4)

I am not sure if you have to conjugate the denominator and multiply it with the top and bottom, then simplify from there or if the 3-4 equals -1 and you end up with i, an imaginary number in the radical. If so, I really do not understand what I would do from there. Please help!

you have to multiply the top by the bottom then conjugate the number you get with the mean

So your question is really:

5/(3√-1)

If you want to make the denominator real, or to "realize" the denominator, then ....

= 5/(3√-1) * (√-1/√-1)
= 5√-1/-3
= -5√-1/3 or -5i/3

Unless there were other imaginary numbers in the rest of your questions, I suspect a typo of sorts here.

To simplify the expression 5 / (3√(3-4)), you need to follow a specific set of steps.

First, let's simplify the part inside the square root: √(3-4).

Since 3-4 equals -1, the expression becomes:
√(-1), which is an imaginary number.

Therefore, the expression 5 / (3√(3-4)) also contains an imaginary number.

To simplify expressions involving imaginary numbers, we can multiply the numerator and denominator by the conjugate of the denominator.

The conjugate of 3√(3-4) is 3√(3-4) itself, as the conjugate of an expression with only real terms remains the same.

So, multiplying the numerator and denominator by the conjugate, we get:
(5 / (3√(3-4))) * (3√(3-4) / 3√(3-4))

Now, we can simplify by multiplying the numerators and denominators:
(5 * 3√(3-4)) / (3 * √(3-4) * 3√(3-4))

Simplifying further, we have:
15√(3-4) / 9√(3-4)

The square root term cancels out:
15 / 9

Finally, we can simplify the fraction:
5/3.

Therefore, the simplified form of 5 / (3√(3-4)) is 5/3.

Note: It's crucial to check the domains and ensure that you're working with real numbers when simplifying expressions. In this case, the expression involves an imaginary number, but the conjugate technique helps in simplifying it.