Chlorine gas + aqueous sodium bromide --> aqueous bromine + aqueous sodium chloride.

I got:
Cl2+2NaBr2(aq)-> Br2(aq)+2NaCl2(aq)
Is this right ?

No. Sodium bromide is NaBr. Sodium chloride is NaCl.

Almost! The balanced equation for the reaction between chlorine gas (Cl2) and aqueous sodium bromide (NaBr) is:

Cl2 + 2NaBr(aq) → 2NaCl(aq) + Br2(aq)

Here's how you can balance the equation step by step:

1. Start by counting the number of each type of atom on both sides of the equation. On the left side, you have 1 Cl and 2 Na, while on the right side, you have 2 Na, 1 Cl, and 1 Br.

Cl2 + 2NaBr(aq) → 2NaCl(aq) + Br2(aq)

2. To balance the chlorines (Cl), add a coefficient of 2 in front of NaCl and Br2:

Cl2 + 2NaBr(aq) → 2NaCl(aq) + 2Br2(aq)

3. Now, count the number of sodium (Na) atoms. We have 2 Na on both sides, so sodium is already balanced.

Cl2 + 2NaBr(aq) → 2NaCl(aq) + 2Br2(aq)

4. Finally, count the number of bromine (Br) atoms. We have 2 Br on the left side (from NaBr) and 2 Br on the right side (from Br2), so bromine is balanced as well.

Cl2 + 2NaBr(aq) → 2NaCl(aq) + 2Br2(aq)

Therefore, the balanced equation is:

Cl2 + 2NaBr(aq) → 2NaCl(aq) + 2Br2(aq)