A moving point is always equidistant from (-3,2) and the line 2x-y+2=0. What is the equation of its locus?

I need help for this problem because I am not very sure of my answer. Thanks in advance.

1 answer

Show us your work

Similar Questions

A moving point is always equidistant from (5,3) and the line 3x+y+5=0. What is the equation of its locus?Please help. how to do

Top answer: the distance of the point (h,k) from the line ax+by+c=0 is d = |ah+bk+c|/√(a^2+b^2) the distance Read more.
A moving point is always equidistant from (-3,2) and the line 2x-y+2=0. What is the equation of its locus?how do you solve this?

Top answer: Sounds like the definition of a parabola: The locus of points equidistant from a point (the focus) Read more.
if a moving point p is always equidistant from the point A(2,4) and the line y=-4, find the equation of the locus of p

Top answer: By definition, that would be a parabola. Using that definition, let any point on the locus be P(x,y) Read more.
Which of the following steps is not part of constructing a perpendicular line to the given line?a. Put any point above or below
Consider the line segment joining A(-1,2) and B(3,4)a) find an equation that expresses the fact that a point P(x,y) is

Top answer: a) arriving at the equation only using your definition for P ..... AP = BP √( (x+1)^2 + (y-2)^2 ) Read more.
Considering the line segment joining A(-5, 2) and B(7, 8), find an equation, in the form of Ax+By=C, that expressed the fact

Top answer: any point on the perpendicular bisector of AB satisfies your requirement. what is the slope of AB ? Read more.
The point X and Y are 8cm apartDraw a scale drawing of the diagram and draw the locus of points that are equidistant from both

Top answer: You're welcome! I'm glad I could help. Locus questions can sometimes be challenging, but with a Read more.
Find the equation of a straight line which is equidistant from the points A(2,3)andB(6,1)

Top answer: To find the equation of a straight line equidistant from two points A(2,3) and B(6,1), we can start Read more.
Find the equation of a straight line which is equidistant from the points (2,3) and (6,1) expressing it in the form ax+by=c

Top answer: the line through those two points has slope -1/2 the line containing all points equidistant from Read more.
A line whose equation is 7y-3x+30=0 passes through the point A and B. Point A on the x-axis while point B is equidistant from x

Top answer: A is at (10,0) B lies on the line y=x, so (3x-30)/7 = x x = -15/2 so B is at (-15/2, -15/2) Read more.