Compute the gravitational force between two 1.00 kg lead spheres whose centers are 1.00 m apart?

Use Newton's Universal Law of Gravity. Look up the value of the constant, G.

F = G*M1*M2/R^2

In your case, M1 = M2 = 1.00 kg
and R = 1.0 m

F = 6.67*10^-11 N

5.7x 10

To compute the gravitational force between two objects, we can use Newton's law of universal gravitation, which states that the gravitational force (F) between two objects is given by the formula:

F = G * (m1 * m2) / r^2

where:
- F is the gravitational force
- G is the gravitational constant (approximately 6.67430 × 10^-11 N(m/kg)^2)
- m1 and m2 are the masses of the two objects
- r is the distance between the centers of the two objects

In this case, both lead spheres have a mass of 1.00 kg and their centers are 1.00 m apart.

Using the given values, we can substitute them into the formula to calculate the gravitational force:

F = (6.67430 × 10^-11 N(m/kg)^2) * ((1.00 kg) * (1.00 kg)) / (1.00 m)^2

Let's plug in the values and calculate the force:

F = (6.67430 × 10^-11 N(m/kg)^2) * (1.00 kg)^2 / (1.00 m)^2

F = (6.67430 × 10^-11 N(m/kg)^2) * 1 kg^2 / 1 m^2

F = 6.67430 × 10^-11 N

Therefore, the gravitational force between the two 1.00 kg lead spheres is approximately 6.67430 × 10^-11 N.

To compute the gravitational force between two objects, you can use Newton's law of universal gravitation formula:

F = (G * m1 * m2) / d^2

Where:
F is the gravitational force between the two objects,
G is the gravitational constant (6.67430 × 10^-11 N(m/kg)^2),
m1 and m2 are the masses of the two objects, and
d is the distance between their centers.

In this case, m1 and m2 are both 1.00 kg, and d is 1.00 m.

Let's substitute these values into the formula to calculate the gravitational force:

F = (6.67430 × 10^-11 N(m/kg)^2 * 1.00 kg * 1.00 kg) / (1.00 m)^2

Simplifying the equation:

F = (6.67430 × 10^-11 N(m/kg)^2 * 1.00 kg^2) / 1.00 m^2

F = (6.67430 × 10^-11 N(m^2/kg^2) * 1.00 kg^2) / 1.00 m^2

F = 6.67430 × 10^-11 N(m^2/kg)

Therefore, the gravitational force between the two 1.00 kg lead spheres whose centers are 1.00 m apart is approximately 6.67430 × 10^-11 N.