The table shows the amount of milk that wisconsin dairy farms produced from 1939 to 1962 which linear model best fits this data?


year milk produced(in billions of lbs
1939 12
1962 15
2005 21

can someone please help

12.5 is wht I got

To determine the linear model that best fits the given data, we can plot the data points on a graph and find the line that represents the data most accurately.

Let's create a table using the given data points:

| Year | Milk Produced (in billions of pounds) |
|------|--------------------------------------|
| 1939 | 12 |
| 1962 | 15 |
| 2005 | 21 |

Now, let's plot these three points on a graph:

(1939, 12)
(1962, 15)
(2005, 21)

After plotting the points, we can see that they form a straight line. To find the linear model that best fits the data, we can use the slope-intercept form of a line:

y = mx + b

Where:
y = dependent variable (milk produced)
x = independent variable (year)
m = slope of the line
b = y-intercept

Let's start by finding the slope (m) using the formula:

m = (y2 - y1) / (x2 - x1)

Using the points (1939, 12) and (1962, 15):

m = (15 - 12) / (1962 - 1939)
m = 3 / 23

Now, let's find the y-intercept (b) by substituting one of the points into the slope-intercept form:

y = mx + b

Using the point (1939, 12):

12 = (3 / 23) * 1939 + b
12 = 2517 / 23 + b
12 = 109.43 + b

Subtracting 109.43 from both sides, we get:

12 - 109.43 = b
b = -97.43

Therefore, the linear model that best fits the given data is:

y = (3 / 23) * x - 97.43

To find the linear model that best fits the data, we need to find the equation of a straight line that passes through these data points.

First, let's plot the given data points on a graph. The x-axis will represent the years, and the y-axis will represent the milk production in billions of pounds.

Data points:
(1939, 12)
(1962, 15)
(2005, 21)

Now, we can draw a straight line that best fits these data points.

To determine the equation of the line, we need to find the slope and the y-intercept. The slope can be calculated using the formula:

slope = (change in y) / (change in x)

Let's use the two data points (1939, 12) and (1962, 15) to calculate the slope:

slope = (15 - 12) / (1962 - 1939)
= 3 / 23
≈ 0.13043

Now, we can find the y-intercept using the formula:

y = mx + b

Using the point (1939, 12), we can substitute the values into the equation and solve for b:

12 = (0.13043)(1939) + b
b ≈ -161.391

Therefore, the equation of the linear model that best fits the given data is:

y = 0.13043x - 161.391

So, the linear model that best fits the data is y = 0.13043x - 161.391, where x represents the year and y represents the milk production in billions of pounds.