solve d/3> or= 6

i mult. both sides by 3/1
d> or=18
Is this correct?
Thanks

yes , d ≥ 18

Yes, your calculation is correct. Multiplying both sides of the inequality d/3 ≥ 6 by 3/1 yields:

(d/3) * (3/1) ≥ 6 * (3/1)
(d * 3) / (3 * 1) ≥ 18 / 1
(d * 3) / 3 ≥ 18
d ≥ 18

So the correct solution is d ≥ 18, which means that the value of d must be equal to or greater than 18 for the inequality d/3 ≥ 6 to hold.