a cubical block of side 2cm is lying on a table. if the density of the material of the cube is 10000kg/m^3. find the pressure exerted by the block on the table.
(g=10m/s^2).
Why we have taken volume=0.000008 m^3
side=2cm=0.02m
volume=0.000008m^3
density=10000kg/m^3
mass=vol*density
=0.000008*10000
=0.08kg
force=mg
=0.08*10
=0.8N
area=0.02*0.02
=0.0004m^2
pressure=force/area
=0.8/0.0004
=8000/4
=2000 pa
To find the pressure exerted by the block on the table, we can use the formula:
Pressure = Force / Area
First, let's calculate the force exerted by the block. The force can be calculated using Newton's second law:
Force = Mass x Acceleration
The mass of the block can be determined using the density and volume of the block. The volume of a cube is given by the formula:
Volume = side^3
Substituting the given side length of the cube (2cm = 0.02m) into the formula, we get:
Volume = (0.02m)^3 = 0.000008m^3
Now we can calculate the mass of the cube using the density and volume:
Mass = Density x Volume
= 10000 kg/m^3 x 0.000008 m^3
= 0.08 kg
Next, let's calculate the force using Newton's second law. The acceleration due to gravity is given as 10 m/s^2:
Force = Mass x Acceleration
= 0.08 kg x 10 m/s^2
= 0.8 N
Now we have the force exerted by the block.
To find the pressure, we need to determine the area over which this force is distributed. In this case, since the block is lying on the table, the entire bottom face of the block will be in contact with the table and exerting force over that area. The area of the bottom face of a cube is given by:
Area of bottom face = side x side
= (0.02m) x (0.02m)
= 0.0004 m^2
Finally, we can calculate the pressure exerted by the block on the table:
Pressure = Force / Area
= 0.8 N / 0.0004 m^2
= 2000 Pa
Therefore, the pressure exerted by the block on the table is 2000 Pascal (Pa).
Divide the block weight by the block's bottom area.
Pressure = (Rho)*g*a^3/a^2 = (rho)*g*a
a is the side length of the cube, in meters.
Rho is the density, in kg/m^ 3
They want you to use a wrong value for g.