An electron moving at a speed of 5 x 10 raise to power 6m/s was shot through a sheet of paper which is 2.1 x 10 raise to power 4cm thick. The electron emerges from the paper with a speed of 2 x 10 raise to power 6 m/s. Find the time taken by the electron to pass through the sheet.
Pls show full working and formular.
v₀ =5•10⁶ m/s
v=2.1•10⁶ m/s
s=2•10⁻⁴ = 2•10⁻⁶ m
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v= v₀-at
a= (v₀-v)/t
substitute 'a' in
s=v₀t+at²/2
and solve for 't'
substitute 'a' in
s=v₀t - at²/2
and solve for 't'
Please save yourself the extra time of writing scientific notation numbers such as
5*10^6
Instead of
5 x 10 raise to power 6.
It is also easier to read.
In the case of this problem, divide the thickness of the paper by the AVERAGE speed of the electron as it passes through. That average speed is
3.5*10^6 m/s.
I think you have omitted an important minus sign. I have never seen a sheet of paper 210 meters thick.
thanks
v=5×10^6
u=2×10^6
s=2.1×10^-6
v^2-u^2=2as==>(5×10^6)^2-(2×10^6)^2=2×a×2.1×10^-6
a=5.2×10^18
v=u+at==>5×10^6=2×10^6+5.2×10^18×t
t=0.6×10^-12
t=6×10^-13
To find the time taken by the electron to pass through the sheet, we can use the equation of motion:
Equation of motion: d = v * t
Where:
d = distance traveled
v = velocity
t = time taken
Given data:
Initial velocity (u) = 5 x 10^6 m/s
Final velocity (v) = 2 x 10^6 m/s
Distance traveled (d) = 2.1 x 10^4 cm = 2.1 x 10^-2 m (converted to meters)
Now, let's find the acceleration (a) experienced by the electron:
Using another equation of motion:
v^2 = u^2 + 2ad
Rearranging the equation:
a = (v^2 - u^2) / (2 * d)
Substituting the values:
a = [(2 x 10^6 m/s)^2 - (5 x 10^6 m/s)^2] / (2 * 2.1 x 10^-2 m)
Calculating the value of a:
a = [4 x 10^12 m^2/s^2 - 25 x 10^12 m^2/s^2] / (4.2 x 10^-2 m)
a = -21 x 10^12 m^2/s^2 / (4.2 x 10^-2 m)
a = -50 x 10^12 m^2/s^2 / m
a = -50 x 10^12 m/s^2
Now, we can use the equation of motion to find the time taken:
v = u + at
Rearranging the equation:
t = (v - u) / a
Substituting the values:
t = (2 x 10^6 m/s - 5 x 10^6 m/s) / (-50 x 10^12 m/s^2)
Calculating the value of t:
t = -3 x 10^6 m/s / (-50 x 10^12 m/s^2)
t = 6 x 10^-8 s
Hence, the time taken by the electron to pass through the sheet is 6 x 10^-8 seconds.