A golf ball was hit and projected in an angle of 60 degrees with the horizontal. if the initial velocity of the ball was 50m/s, calculate the following:
a. the time the golf ball was in the air
b. horizontal distance the ball traveled
c. maximum height the ball reached

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  1. a) 2 Vo sin60/ g

    b) 2 Vo^2 sin60 cos60/g = Vo^2 sin120/ g

    c) Vo^2*sin^2 60/(2g)

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  2. nlj

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  3. 8.83 s
    221 m
    95.66 m

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  4. Can i see the formula?

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  5. May i have your formula please!

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