Three security cameras were mounted at the corners of a triangular parking lot. Camera 1 was 151 ft from camera 2, which was 122 ft from camera 3. Cameras 1 and 3 were 139 ft apart. Which camera had to cover the greatest angle?

Camera 3, because when you draw out the triangle the largest side is across the largest angle.

To determine which camera had to cover the greatest angle, we need to understand the geometry of the situation. In a triangle, the angles are related to the lengths of the sides.

Let's call the three cameras A, B, and C. Based on the information provided, we can determine the lengths of the sides of the triangle formed:

Camera A is 151 ft from Camera B.
Camera B is 122 ft from Camera C.
Camera A and C are 139 ft apart.

To find the angles, we can use the Law of Cosines, which states that c^2 = a^2 + b^2 - 2ab*cos(C), where c is the side opposite angle C.

Calculating the angles for each camera:

Angle A = arccos((122^2 + 139^2 - 151^2) / (2 * 122 * 139))
Angle B = arccos((151^2 + 139^2 - 122^2) / (2 * 151 * 139))
Angle C = arccos((122^2 + 151^2 - 139^2) / (2 * 122 * 151))

Now, compare the three angles to determine which one is the greatest.