A rectangular field is 35 m longer than it is wide. The length of the fence around the
perimeter of the field is 290 m. What are the dimensions (length and width) of the
fence?
thank you :D it helped me understand
What don't you understand about the answer I posted a few minutes ago?
http://www.jiskha.com/display.cgi?id=1357334581
i didn't see it before thank you for answering my question it helped :D
you put 390 instead of 290 for the perimeter why? it has me a bit confused.
Oops! I'm sorry. That was a typo.
P = 2L + 2W
290 = 2(W + 35) + 2W
290 = 2W + 70 + 2W
220 = 4W
55 = W
To find the dimensions of the fence, we need to set up a mathematical equation based on the information given.
Let's assume the width of the field is x meters.
According to the problem, the length of the field is 35 meters longer than the width. So, the length of the field would be x + 35 meters.
The perimeter of a rectangle is given by the formula P = 2L + 2W, where P is the perimeter, L is the length, and W is the width.
In this case, the perimeter of the field is given as 290 meters.
So, we can set up the following equation based on the given information:
2(x + 35) + 2x = 290
Now, let's solve this equation to find the value of x, which represents the width of the field.
First, distribute the 2 to both terms in the parentheses:
2x + 70 + 2x = 290
Combine like terms:
4x + 70 = 290
Subtract 70 from both sides:
4x = 220
Divide both sides by 4:
x = 55
Now that we have found the width of the field (x = 55 meters), we can substitute this value back into the expression for the length:
Length = x + 35 = 55 + 35 = 90 meters
Therefore, the width of the field is 55 meters, and the length of the field is 90 meters.