what are the values of a,b,c and d in the balanced chemical equation
aFe^2+(aq)+bAl(s)=cFe(s)+dAl^3+(aq)
where a,b,c and d are the lowest possible whole numbers?
a=
b=
c=
d=
Each Fe+2 ion gets two electrons
Each Al loses three electrons. So, for each three Fe+2 ions, one must have two Al atoms.
a=3
b=2
c=3
d=2
3Fe+2 +2Al(s)=3Fe(s)+2Al+3(aq)