The temperature of a dilute 0.847 M solution of NaBr was increased from 25 degrees Celcius to 40 degrees Celcius. What effect did this temperature change have on the molarity of the NaBr solution?
Note the correct spelling of celsius.
As the temperature is raised the volume increases. M = mols/L. What happens if L becomes larger?
To determine the effect of temperature change on the molarity of a solution, we need to consider the concept of temperature coefficient for molarity.
The temperature coefficient for molarity is a measure of how the molarity of a solution changes with temperature. It is denoted by the Greek letter alpha (α) and is specific to each solute and solvent combination. The temperature coefficient can be positive, negative, or zero.
To find the effect of temperature change on the molarity of a solution, we need to calculate the change in molarity (ΔM) using the formula:
ΔM = M * α * ΔT
where:
ΔM = change in molarity
M = initial molarity
α = temperature coefficient for molarity
ΔT = change in temperature
In this case, the initial molarity (M) is given as 0.847 M. The change in temperature (ΔT) is 40°C - 25°C = 15°C.
The temperature coefficient for molarity of NaBr in water is small and approximately zero. This means that the molarity of the solution does not change significantly with temperature. Therefore, we can assume α = 0.
Using the formula, we can calculate the change in molarity (ΔM):
ΔM = 0.847 M * 0 * 15°C = 0
Therefore, the temperature change from 25°C to 40°C has no effect on the molarity of the NaBr solution. The molarity remains the same at 0.847 M.