Find two consecutive positive integers whose product is 132.

11*12 = 132

To find two consecutive positive integers whose product is 132, we can set up an equation.

Let's assume the first positive integer is x.
The next consecutive positive integer would then be x + 1.

The equation we can write is:
x * (x + 1) = 132

Expanding the equation, we get:
x^2 + x = 132

Rearranging the equation, we have:
x^2 + x - 132 = 0

Now, we can solve this quadratic equation to find the values of x.

Factoring the equation, we get:
(x - 11)(x + 12) = 0

Setting each factor equal to zero, we have:
x - 11 = 0 or x + 12 = 0

Solving for x, we find:
x = 11 or x = -12

Since we're looking for positive integers, we can disregard the negative solution.

Therefore, the two consecutive positive integers whose product is 132 are:
11 and 12.

To find two consecutive positive integers whose product is 132, we can use a mathematical approach:

Let's assume the first positive integer is x
The next consecutive positive integer is x+1

According to the problem, their product is 132:
x * (x+1) = 132

So, we can set up this equation and solve it to find the values of x and x+1:

x^2 + x = 132

Rearranging the equation:

x^2 + x - 132 = 0

To solve this quadratic equation, we can either factorize it or use the quadratic formula.

Factorizing method:
(x + 12)(x - 11) = 0

Setting each factor to zero and solving for x:

x + 12 = 0 or x - 11 = 0

x = -12 or x = 11

Since we are looking for positive integers, we discard the negative solution, so the first positive integer is x = 11.

The next consecutive positive integer is x+1 = 11 + 1 = 12.

Therefore, the two consecutive positive integers whose product is 132 are 11 and 12.

x(x+1)=132

x^2+x=132
x^2+x+132=0
(x+12)(x-12)=0
x=-12 x=12