Algebra II

The weight of a body varies inversely as the square of its distance from the center of the earth. If the radius of the earth is 4000 mi, how much would a 200 lb man weigh 1000 mi above the surface of the earth?

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1. w = k(1/d^2)

when d = 4000 , w = 200
200 = k(1/16000000)
k = 200(16000000)

when d = 5000
w = 200(16000000)/5000^2 = 128

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posted by Reiny

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