# calculus

integrate the following
(3y-7x-3)dx+(7y-3x-7)dy=0

1. rearrange things a it to get

(3y-7x-3)+(7y-3x-7)y'=0
now integrate term by term
3xy-7/2x^2-3x + 7/2y^2-3xy-7y=0

the 3xy's go away; multiply by 2/7 to get

-(x^2+6/7)+(y^2-2y) = 0
-(x+3/7)^2+(y-1)^2 = 58/49

an hyperbola opening up and down

posted by Steve

First Name

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