what is the magnitude of the resultant of a 6.0n force acting vertically upward and a 4.0n force acting horizontally

Since those two forcesw are perpendicular, the magnitude is

sqrt[6^2 + 4^2] = sqrt52 N = 7.21 N

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Ah, the magnitude of the resultant force! Let's calculate it using the Pythagorean theorem. If we consider the 6.0N force as the vertical component and the 4.0N force as the horizontal component, we can create a right triangle of forces. Now, let's bring in our sense of humor to make it more enjoyable!

Imagine the 6.0N force trying to reach new heights like a superstar pop singer, and the 4.0N force trying to become a famous rock guitarist by going horizontally. These two forces are quite the dynamic duo!

Now, let's grab our math cape and calculate the magnitude of the resultant! According to the Pythagorean theorem, we have:

Resultant magnitude^2 = (6.0N)^2 + (4.0N)^2

Resultant magnitude^2 = 36N^2 + 16N^2

Resultant magnitude^2 = 52N^2

And there you have it! The magnitude of the resultant force is the square root of 52N^2. But let's keep things simple, and simplify it as:

Resultant magnitude = √(52N^2)

Now go forth, my friend, armed with this knowledge and the power of music-inspired forces! May you rock and reach new heights!

To find the magnitude of the resultant force, we can use the Pythagorean theorem. The Pythagorean theorem states that in a right triangle, the square of the hypotenuse (c) is equal to the sum of the squares of the other two sides (a and b).

In this case, let the vertical force be represented by "a" and the horizontal force be represented by "b". The resultant force is represented by "c". According to the problem, a = 6.0 N and b = 4.0 N.

Using the Pythagorean theorem, we can find the magnitude of the resultant force, c, as follows:

c^2 = a^2 + b^2
c^2 = (6.0 N)^2 + (4.0 N)^2
c^2 = 36.0 N^2 + 16.0 N^2
c^2 = 52.0 N^2

To find c, we take the square root of both sides of the equation:

c = √(52.0 N^2)
c ≈ 7.21 N

Therefore, the magnitude of the resultant force is approximately 7.21 Newtons.