What is the value of the degree of polymerization n of isotactic PB with a molecular weight of 3.091×105 g/mol?
The empirical formula is C3H8.
The polymer is (C3H8)n.
3.091E5/empirical mass = n.
wrong...the mer unit is C4H8 with a molecular weight of 56g/mol therefore n is 3.091e5/56 = 5520
To determine the degree of polymerization (n) of isotactic PB (Polybutene), you need to know the molecular weight of the polymer.
The degree of polymerization (n) is the average number of repeating units in the polymer chain. It can be calculated using the following equation:
n = Mw / Mm
Where:
- n is the degree of polymerization
- Mw is the molecular weight of the polymer
- Mm is the molecular weight of the repeating unit
In this case, you are given the molecular weight of the polymer (3.091×10^5 g/mol). To find the value of n, you also need to know the molecular weight of the repeating unit for isotactic polybutene.
The molecular weight of the repeating unit for isotactic polybutene is determined by dividing the molecular weight of the polymer by the number of repeating units in one polymer chain.
However, the molecular weight of the repeating unit is not provided in the question. Without this information, it is not possible to determine the degree of polymerization (n) for isotactic PB.