f(x)=In(x+1)+1 Please show work
y = ln(x+1) + 1 inverse: x = ln(y+1) + 1 x-1 = ln(y+1) solving for y .... y+1 = e^(x-1) y = e^(x-1) - 1 or f^-1 (x) = e^(x-1) - 1
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