ANDY HAS TWICE AS MANY MARBLES AS PANDY AND SANDY HAS HALF AS MANY HAS ANDY AND PANDY PUT TOGETHER .ANDY HAS 110 MARBLES WHICH IS 115 MARBLES LESS THAN SANDY.HOW MANY MARBLES EACH OF THEM HAVE
First, please do not use all capitals. Online it is like SHOUTING. Not only is it rude, but it is harder to understand. Thank you.
A = 2P = 110
S = .5(P + 2P) = .5 (55 + 110) = 82.5
It doesn't make sense, since they can't have a half marble. Is there a typo?
With your data, Andy is a no-brainer, 110.
Sandy = 110 + 115 = 225
2P = 110 therefore Pandy has 55.
Let's break down the information given in the question and solve it step by step:
1. Andy has twice as many marbles as Pandy.
2. Sandy has half as many marbles as Andy and Pandy combined.
3. Andy has 110 marbles, which is 115 marbles less than Sandy.
Let's assume the number of marbles Pandy has is "x."
From the first statement, we know that Andy has twice as many marbles as Pandy, so Andy has 2x marbles.
According to the second statement, Sandy has half as many marbles as Andy and Pandy combined. Therefore, Sandy has (2x + x)/2 = 3x/2 marbles.
Now, we are told that Andy has 110 marbles, which is 115 marbles less than Sandy. We can write this as an equation:
3x/2 - 110 = 115.
Simplifying the equation:
3x/2 = 110 + 115,
3x/2 = 225,
3x = 2 * 225,
3x = 450,
x = 450/3,
x = 150.
So, Pandy has 150 marbles.
Andy has twice as many marbles as Pandy, which means Andy has 2 * 150 = 300 marbles.
Sandy has half as many marbles as Andy and Pandy combined, so Sandy has (2 * 150 + 150)/2 = 450/2 = 225 marbles.
In conclusion, Pandy has 150 marbles, Andy has 300 marbles, and Sandy has 225 marbles.