# maths --plse help me..

In a pentagon ABCDE, angle B = 168, angle C:angleD = 23:25 and AB//ED. Find angle C and angle D.

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1. since AB║DE, adding exterior angles at B,C,D = 180

(180-B)+(180-C)+(180-D) = 180
∠B+∠C+∠D = 360
168 + 23x + 25x = 360
48x = 192
x = 4

∠C = 92
∠D = 100

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posted by Steve

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