There are three mixtures of equal capacity and all are completely filled with acid and water mixtures in diferent ratios.

The ratio of acid to water in the first container is 2:3 ,in second 3:7 and third 4:11.

If the mixtures of all the containers are mixed together ,what is the ratio of acid to water in it?

(2+3+4):(3+7+11) = 9:21 = 3:7

To find the ratio of acid to water in the mixture obtained by combining all three containers, we need to calculate the total amount of acid and water in each container and then add them together.

Let's start with the first container. The ratio of acid to water is 2:3. This means that for every 2 units of acid, there are 3 units of water. Since the container is completely filled, we can assume it contains 2x units of acid and 3x units of water, where x is a common constant.

Similarly, for the second container with a ratio of acid to water of 3:7, we can assume it contains 3y units of acid and 7y units of water.

For the third container with a ratio of acid to water of 4:11, we can assume it contains 4z units of acid and 11z units of water.

Now, when we mix all three containers together, the total amount of acid will be 2x + 3y + 4z units, and the total amount of water will be 3x + 7y + 11z units.

To find the ratio of acid to water in the mixture, we need to simplify these totals as much as possible. However, since we do not have the exact values for x, y, and z, we can only express the ratio in terms of these variables.

Thus, the ratio of acid to water in the mixture obtained by combining all three containers is:

(2x + 3y + 4z) : (3x + 7y + 11z)

This is the most simplified form of the ratio without knowing the exact values of x, y, and z.