calculus

form a polynomial with real coefficients have given degree and zeros.
degree 5, zeros 9, -i; 8+i

please show work

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  1. complex roots are in pairs, so we have
    (x-9)(x+i)(x-i)(x-(8+i))(x-(8-i))
    (x-9)(x^2+1)((x-8)^2 + 1)

    . . .

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    posted by Steve

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