What is the number of water molecules that will form from 30 g of NO

For NO, 30 g is one mole.

One mole contains Avogadro's number of molecules. That is 6.02*10^23

My question is: what reaction is being used to form H2O from NO?
Perhaps it is
2H2(g)+2NO(g)--> N2(g)+2H2O(g)

If so, each NO mole forms one H2O mole.