Try MgBr2 and I expect you can balance it.
i got a balancing equation problem
i gotta get this to balance
Mg(OH)2+ HBr --> MgBr + H20
so far i'v gotten it down to
2Mg(OH)2+ 4HBr --> 2MgBr + 4H20
but it's still not balanced,so can someone please balance this
u can only add the number in front of the MgBr(and same with the others),so i can't add the 2 at the end of it
That's good advice and one which I have stressed to my students; i.e., one may NOT balance equations by changing the subscripts. :-:). However, this advice doesn't hold when you change the subscript because it is incorrect. That is, the formula for magnesium bromide IS MgBr2 and not MgBr. So in this case make it MgBr2 and see if it isn't easier to balance. Mg is in group 2 (or IIA) and Br is in group 17(or VIIA). Mg has two electrons to give away and Br needs just one; therefore, we need two Br atoms per one Mg atom and the formula is MgBr2. =).
hmmm this must be a mistake on my sheet then as i also agree with that it should be a MgBr2
so far it is:
2Mg(OH)2 + 4HBr --> 2MgBr2 + 4H20
hopefully that is correct and both sides are balanced
That looks balanced to me, too. I'm sure its just a typo on the sheet.
Yes, you're correct. The balanced equation is:
2Mg(OH)2 + 4HBr → 2MgBr2 + 4H2O
By ensuring that there are equal numbers of each type of atom on both sides of the equation, we can determine the coefficients needed to balance the equation. In this case, we have:
On the left side: 2 magnesium (Mg), 4 oxygen (O), 8 hydrogen (H), and 4 bromine (Br)
On the right side: 2 magnesium (Mg), 8 oxygen (O), 8 hydrogen (H), and 4 bromine (Br)
To balance the equation, we need to make sure that the number of each type of atom is the same on both sides. We can do this by adjusting the coefficients in front of each compound. In this case, we can see that:
- There are 2 magnesium (Mg) atoms on the left side, so we need 2 magnesium bromide (MgBr2) on the right side.
- There are 4 hydrogen (H) atoms on the left side, so we need 4 water (H2O) molecules on the right side.
After making these adjustments, the balanced equation becomes:
2Mg(OH)2 + 4HBr → 2MgBr2 + 4H2O
Now, the equation is balanced with an equal number of each type of atom on both sides.