I need help drawing these structures.

2-chloro-3-ethylhexanal

2,2-dimethylcyclopentanol

5,5,7-triiodo-trans-3-nonene

para-bromomethylbenzene

Thanks for the help I'm having hard time with these.

You can see from your attempt at drawing structures that this site can't handle spaces. We can't draw structures on this forum.

I understand but I thought maybe someone could explain it.

If you will type in the name in google sometimes it will give you a site showing the structure. If you get one with Wikipedia, that almost always shows a structure.

Sure, I can help you draw these structures! Let's take it one by one:

1. 2-chloro-3-ethylhexanal:
To draw this structure, start with a straight chain of six carbons. Since it's a "2-chloro," add a chlorine atom on the second carbon. And since it's a "3-ethyl," add an ethyl group (a two-carbon chain) on the third carbon. Lastly, add an aldehyde functional group (-CHO) at the end of the chain. The final structure should look like this:
CH3-CH2-CH(Cl)-CH2-CH2-CHO

2. 2,2-dimethylcyclopentanol:
To draw this structure, start by drawing a cyclopentane ring (a five-membered carbon ring). Since it's "2,2-dimethyl," add a methyl group (CH3) on the second carbon and another methyl group on the second carbon of the first methyl group. Lastly, add an alcohol functional group (-OH) on one of the carbons in the ring. The final structure should look like this:
CH3-C(CH3)(CH3)-C(OH)-CH2-CH2

3. 5,5,7-triiodo-trans-3-nonene:
To draw this structure, start with a straight chain of nine carbons. Since it's "3-nonene," add a double bond between the third and fourth carbon. Since it's "trans," make sure the two largest groups on each side of the double bond are on opposite sides. Now, it's a "5,5,7-triiodo," so add three iodine atoms on the fifth carbon and two iodine atoms on the seventh carbon. The final structure should look like this:
CH2=CH-CH(I)-CH(I)-CH(I)-CH2-I-CH2-CH2-CH3

4. para-bromomethylbenzene:
To draw this structure, start with a benzene ring (a six-membered carbon ring with alternating double bonds). Since it's "para," add a bromine atom on the carbon opposite to the methyl group. Lastly, add a methyl group (-CH3) on one of the carbons of the benzene ring. The final structure should look like this:
CH3-CH2-CH2-CH(Br)-C6H4

I hope this helps! Let me know if there's anything else I can assist you with.