A cyclopropane-oxygen mixture is used as an anesthetic. If the partial pressure of cyclopropane in the mixture is 334 mmHg and the partial pressure of the oxygen is 1.02 atm, what is the total pressure of the mixture in torr?
P t = P a + P b + P c +
so that being said....
P total = P C3H6 + P O2
= 330 mm Hg + 760 mm Hg
= 1090 mm Hg
From there on i think you can figure it out. Its a fun problem. My chem teacher gave one like it to our class....
To find the total pressure of the mixture, we need to convert the partial pressures of cyclopropane and oxygen to the same unit, and then add them together.
Partial Pressure of Cyclopropane:
Given: 334 mmHg
Partial Pressure of Oxygen:
Given: 1.02 atm
Conversion of Oxygen partial pressure to mmHg:
1 atm = 760 mmHg
1.02 atm = 1.02 * 760 mmHg = 775.2 mmHg
Total Pressure:
Total Pressure = Partial Pressure of Cyclopropane + Partial Pressure of Oxygen
Total Pressure = 334 mmHg + 775.2 mmHg
Now, let's add the pressures:
Total Pressure = 1109.2 mmHg
Therefore, the total pressure of the mixture is 1109.2 mmHg.
To find the total pressure of the mixture in torr, we need to convert the partial pressures of cyclopropane and oxygen to the same unit.
1. Convert the partial pressure of cyclopropane from mmHg to atm:
Since 1 atm = 760 mmHg, we can calculate the partial pressure of cyclopropane in atm as follows:
Partial pressure of cyclopropane (atm) = 334 mmHg / 760 mmHg/atm
2. Convert the partial pressure of oxygen to atm:
The partial pressure of oxygen is already given in atm, so we don't need to convert it.
3. Calculate the total pressure of the mixture:
Total pressure of the mixture (atm) = Partial pressure of cyclopropane (atm) + Partial pressure of oxygen (atm)
4. Convert the total pressure of the mixture from atm to torr:
Since 1 atm = 760 torr, we can calculate the total pressure of the mixture in torr as follows:
Total pressure of the mixture (torr) = Total pressure of the mixture (atm) * 760 torr/atm
Now, let's substitute the values and calculate the total pressure of the mixture in torr:
Partial pressure of cyclopropane (atm) = 334 mmHg / 760 mmHg/atm
Partial pressure of oxygen (atm) = 1.02 atm
Total pressure of the mixture (atm) = Partial pressure of cyclopropane (atm) + Partial pressure of oxygen (atm)
Total pressure of the mixture (torr) = Total pressure of the mixture (atm) * 760 torr/atm
After performing the calculations, you will find the final answer: the total pressure of the mixture in torr.