Tracy (of mass 49 kg) and Tom (of mass
65 kg) are standing at rest in the center of the
roller rink, facing each other, free to move.
Tracy pushes off Tom with her hands and remains in contact with Tom’s hands, applying
a constant force for 0.5 s. Tracy moves 0.35 m
during this time. When she stops pushing off
Tom, she moves at a constant speed.
What is Tracy’s constant acceleration
during her time of contact with Tom?
Answer in units of m/s
2
12
To find Tracy's constant acceleration during her time of contact with Tom, we can use the equation:
acceleration = change in velocity / time
Tracy starts at rest and ends up moving at a constant speed, so her change in velocity is the final velocity minus the initial velocity, which is 0 (since she starts at rest). Therefore, the change in velocity is just the final velocity.
Given that Tracy moves 0.35 m in 0.5 s, we can calculate her final velocity using the equation:
final velocity = distance / time
final velocity = 0.35 m / 0.5 s = 0.7 m/s
Now, we can calculate Tracy's constant acceleration:
acceleration = final velocity / time
acceleration = 0.7 m/s / 0.5 s = 1.4 m/s^2
Therefore, Tracy's constant acceleration during her time of contact with Tom is 1.4 m/s^2.
To find Tracy's constant acceleration during her time of contact with Tom, we can use the equation for acceleration:
acceleration = (change in velocity) / time.
We know that Tracy moves 0.35 m during this time (her displacement), but we need to find her change in velocity.
Since Tracy starts at rest, her initial velocity is 0 m/s. After pushing off Tom and moving at a constant speed, her final velocity is also 0 m/s.
Using the equation for acceleration, we have:
acceleration = (change in velocity) / time
acceleration = (final velocity - initial velocity) / time
Since both final and initial velocity are 0 m/s, the change in velocity is also 0 m/s.
Therefore, Tracy's constant acceleration during her time of contact with Tom is 0 m/s².