algebra

What are the exact solutions?

x^2+4x+4=36

I have -34,-38

Is this right?

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  1. I am not exactly sure if this answer is correct. I ran it through my Calculator and here is what I get..

    X2+4x+4=36

    = x2+4x-32=0

    =x2-4x+8x-32=0

    =x(x2/x – 22*x/x) + 23 (23*x/23- 25/23) = 0

    = x(x-4) +23 (x-4) = 0

    = (x-4) (x+8) = 0

    = x - 4 = 0

    = x +4 = 0

    X = 4
    X = -8

    X = 4, -8

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  2. Becky, why did you not substitute your answers back in the equation.
    It would have shown you that you are way off,
    but Mike's answers work and his solution is correct.

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