# algebra

What are the exact solutions?

x^2+4x+4=36

I have -34,-38

Is this right?

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1. I am not exactly sure if this answer is correct. I ran it through my Calculator and here is what I get..

X2+4x+4=36

= x2+4x-32=0

=x2-4x+8x-32=0

=x(x2/x – 22*x/x) + 23 (23*x/23- 25/23) = 0

= x(x-4) +23 (x-4) = 0

= (x-4) (x+8) = 0

= x - 4 = 0

= x +4 = 0

X = 4
X = -8

X = 4, -8

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2. Becky, why did you not substitute your answers back in the equation.
It would have shown you that you are way off,
but Mike's answers work and his solution is correct.

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