A hockey player makes a slap shot, exerting a constant force of 31.4 N on the hockey puck for 0.13 s. What is the magnitude of the impulse given to the puck?
Well, if the hockey player had given the puck a name, like "Bob" or "Slappy," then the magnitude of the impulse given to Bob or Slappy would be 31.4 Newton-seconds. But since we're talking about the puck, let's just call it "Slippy." So the magnitude of the impulse given to Slippy is still 31.4 Newton-seconds. Slippy might have thought it was a real slap in the face, though!
To find the magnitude of the impulse given to the puck, we can use the formula:
Impulse = Force x Time
Given:
Force = 31.4 N
Time = 0.13 s
Substituting these values into the formula, we have:
Impulse = 31.4 N x 0.13 s
Calculating this expression, we find:
Impulse = 4.082 N·s
Therefore, the magnitude of the impulse given to the puck is 4.082 N·s.
To find the magnitude of the impulse given to the puck, we can use the formula:
Impulse = Force × Time
In this case, the force exerted by the hockey player is 31.4 N, and the time for which the force is exerted is 0.13 s. Plugging in these values into the formula:
Impulse = 31.4 N × 0.13 s
Impulse ≈ 4.082 N·s
Therefore, the magnitude of the impulse given to the puck is approximately 4.082 N·s.