6a=(5(3+b+a)-9, find value of a; 3(a-b)+4b=5(1+6), find value of b
Parentheses come in pairs. You have two left parentheses and one right parenthesis, so I do not know what you mean.
Solve by substitution:
6a=5(3+b+a)-a; find value of a
3(a-b)+4b=5(1+b); find value of b
Solve by substitution:
6a=5(3+b+a)-a; find value of a
3(a-b)+4b=5(1+b); find value of b
To find the value of a in the equation 6a = (5(3 + b + a) - 9), we can simplify the equation step by step using algebra.
1. Distribute the 5 inside the parentheses: 6a = (15 + 5b + 5a - 9).
Simplify this to: 6a = (6a + 5a + 5b + 6).
2. Combine like terms on the right side of the equation: 6a = (11a + 5b + 6).
3. Move the variables to one side and the constant to the other side: 6a - 11a = 5b + 6.
4. Combine like terms on both sides: -5a = 5b + 6.
5. Divide both sides by -5 to solve for a: a = (5b + 6) / -5.
Therefore, the value of a is (5b + 6) / -5.
Now, let's move on to finding the value of b in the equation 3(a - b) + 4b = 5(1 + 6).
1. Distribute the 5 on the right side of the equation: 3(a - b) + 4b = 5(7).
2. Simplify inside the parentheses: 3a - 3b + 4b = 35.
3. Combine like terms on the left side: 3a + b = 35.
4. Subtract 3a from both sides to isolate b: b = 35 - 3a.
Therefore, the value of b is 35 - 3a.