A 608g sample of water at 77C is mixed w/429g of water at 23C. What is the final temp of the mixture? Assume no heat liss to the surroundings.
Answer in units of C
deltaQ = 0; where Q = m*C*T
m is the mass, C is the specific heat, T is the temperature
608*C*(Tf-77) + 429*C*(Tf-23) = 0
Where Tf is the final temperature
Solve for Tf